Platinum Cannon Shipwreck
In what form can the energies be stored? Before stating an opinion of this question, one must accept the fundamental interactions of elementary particle physics to be in error, or at least f or nuclear reactions what occur at lower energies. There are two troubled areas:
1. The equation E=mc2 can not be generalized to energies and interactions different from the electro-magnetic ones. Gravity is considered so weak that it only reacts when amounts of mass are involved.
2. Contrary to the principles of relativity, a material medium exists, and this media is able to collect potential energy which can change into matter. The Electro?weak Interaction, which is intimately tied to the deep principals of special relativity, is this transfer mechanism. When the low energy transmutation reaction starts, the energies present are not of sufficient quantum as required by the existing conservation laws.
In addition, this particular nuclear reaction only occurs when the starting isotope has a magnetic moment. it is assumed when the nucleus is placed with a resonance field and stored, it is then qualitized to a specific precession. This nucleus will store energy through different reactions within the surrounding force field. At the point when Q is greater than required to break the alpha bond, only then will the nucleus emit an alpha particle. To understand fully, we will divide the reactions into their two categories, the positive energy reaction and the negative energy reaction.
To start the positive energy reaction, it is necessary for the nucleus to store energy in a way which is different than is supposed by classical quantum mechanics, up to the point where an alpha particle can tunnel through the classical coulomb barrier.
In this reaction, such as the Hg199 - Pt195 = a, the energies from the ground state must only be increased to a level of (x), at which time the alpha particle can tunnel through the nuclear barrier.
In the case of the negative energy reaction, the nuclear pathway is most difficult, for it is necessary to "pump" energy into the nucleus which will store it until the fission of the alpha particle can occur. An example of the negative energy reaction is:
Ag107 ----> Rh103 + a
In this case, it is necessary to increase the mass of the starting nucleus to a quantum greater than Q of the transitional level required for a mass balance after fission.
After completion of over three hundred(300) experiments, I have seen that the previously mentioned reaction can only be accomplished on isotopes with magnetic moments. An example of this is mercury which has seven stable isotopes found in nature, but only Hg199 and Hg201 have the required magnetic moment. These isotopes gave the following reactions:
Hg199 ---> Pt191 + a
Hg201 ---> Pt197 + a ---> AU197 + b
After detailed mass spectroscopy studies, the only platinum isotopes found were the ones noted above. Numerous other examples were seen in the laboratory with multiple isotopic elements. This proved the reaction to be limited to isotopes with magnetic moments.
If one could accept the fact
that the symmetrical planetary models of the atom are inconsistent with
the actual structure, it then would be logical to accept an asymmetrical
model of the nucleus as postulated by others in the past. With an asymmetrical
body, the columbic field itself could not be symmetrical, nor could
it be uniform in repulsion energies. This can account for the ease in
tunneling of the alpha transmutations. And the asymmetrical model may
explain why the primary transmutations seen in the low energy fission
of isotopes with the magnetic moments was always an alpha particle.
Secondary and tertiary nuclear reactions will occur only if the isotopes
produced from the alpha fission were unstable. Normal decay will then
occur typically through a beta or positron emission.